A half dollar has diameter of 3*10^-2 . If an atom has a diameter of 5*10^-10 meter, about how many of those atoms could fit across the diameter of the coin?

Question

A. 6*10^8

B. 6*10^7

C. 1.7*10^-8

D. 1.7*10^-12

Answer 1

(3x10^-2)/(5x10^-10)

3/5 x 10^-2 x 10¹⁰

0.6 x 10⁸

6 x 10⁷

 

(B)