if a basketball team record is 42 wins and 32 loses how many games they need to win to reach 60%

Question

it talks about percentage win and loses word problem algebra 2

Answer 1

You try to win every game

Answer 2

So far, they have won 42 games out of the 74 that have been played. (that's a win percentage of about 56.8%)

 

 

 

Let x = number of additional wins needed to have a 60% win percentage.

 

So, we need to solve the equation (x+42)/(x+74) = 0.60

 

(x+42)/(x+74) = 3/5

 

5(x+42) = 3(x+74)

 

5x + 210 = 3x + 222

 

        2x = 12

 

         x = 6

 

So, if they win their next 6 games, they will have won 48 out of 80 games, which is a 60% win percentage.  

 

 

Answer 3

The key to this problem is to realize that 32 is where we need to start to solve this problem.  Because it is the number of games lost we need to figure out what number can be added to it and be %60 of that sum.

 

# of wins (w) + 32 loses = # of games (g)

    %60          %40          %100

 

We know that 32 needs to be %40 of the total (that makes the other value %60).

32 is %40 of g...

32=0.40g divide both sides by 0.40

80=g

 

w+32=80

w=48

 

but we are not done...

the question is how many do they need to win to make the %60

 

they already have 42 so they need 6 more wins assuming they have no more losses

 

Answer 4

This question is not about Basketball it’s about calculating percentages and that makes it a question for the math department. Games will not be one and lost because a team does or does not know how many games they need to win. There goal should be to win every game possible and to play well, even in the ones they lose. You might try to departmentalize your questions a little better.