Andrew M. answered • 02/09/16

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

x

^{2}/(4x-3)The domain is all possible input values for x

The only restriction is that we cannot divide by zero so

set 4x-3=0 and solve to find the restriction..

4x-3 = 0 add 3 to both sides

4x=3 divide both sides by 4

x = 3/4

The only restriction is x cannot equal 3/4 or .75

**In interval notation this is: (-∞, 3/4)U(3/4, ∞)**

The open parentheses denote that the value 3/4 and ∞ are not included.

If you are more comfortable with showing the domain as an inequality

we have:

[-∞ < x <3/4] U [3/4 < x < ∞]