Alex C.

asked • 02/07/16

How do I factor 9-(2x+1)^2

Hi , I need help with factoring  9-(2x+1)^2 

Kenneth S.

If you let z = (2x+1) you can rewrite the problem as 32 - z2 and that's the DIFFERENCE OF SQUARES;
factoring gives (3 - z)(3+z).
 
Now substitute for z and you'll have
[3 - (2x + 1)][3+2x +1].
 
Simplify (remember to distribute the - sign) and you have (2 -2x)(4 + 2x) and this can have 2 factored out twice, giving 4(2 + x)(1-x).
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02/07/16

1 Expert Answer

By:

Michael J. answered • 02/07/16

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