Mark M. answered 01/30/16
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Mathematics Teacher - NCLB Highly Qualified
A = A0(0.5)t/h. where t = time, h = half life, A0 = initial amount
0.0625A0 = A0(0.5)t/80 divide both sides by A0
0.0625 = (0.5)t/80 take ln of both sides
ln 0.0625 = (t/80) ln 0.5 calculate
-2.77258872 ≈ (t/80)(-0.693147181)
4 ≈ t/80
320 = t
After three hundred twenty hours 1/16 of the original amount remains.
Now the non-algebraic method.
80 hours, 1/2
160 hours, 1/4
240 hours, 1/8
320 hours, 1/16