Word problem with fraction

Question

Larry spent half of his money on a camera and another 1/8 on a radio. The camera cost $120 more than the radio. How much money did he have at first?

Answer 1

Larry spent 1/2 of his money on a camera and 1/8 on a radio.

 

This is the same as saying that Larry spent 4/8 of his money on the camera and 1/8 on the radio.

 

Then he spent 3/8 more on the camera.

 

The problem says that he spent $120 more on the camera.

 

This means that 1/8 + 1/8 + 1/8 = 120

 

What do I add to itself three times to get 120?

 

40, so 1/8 of his money must have been $40.

 

Then 8/8 of his money, or ALL of his money must be...

 

$320

 

because 8x40 = 320.

 

He must have started out with $320.