How do you solve sin(x)cot(x)=0?

Question

This is a trigonometry identity equation. 

Answer 1

sin(x)cot(x)=0

cot(x)=cos(x)/sin(x)

sin(x)(cos[x]/sin[x])=0

cos(x)=0  (the two sin(x)'s cancel)

on the unit circle...

cos is 0 at 90º and at 270º