Sarah W. answered 01/23/16
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I Can Help You With Math!
Let's figure this out by first asking ourselves how many groups of 30 there are in 148.
148/30 = 4 and 28/30 = 4 and 14/15
That we have at least 4 groups of 30 tells us that since we have 3 colorless kites for each of those four groups and 4 tail-less kites for each of those four groups we have
12 colorless kites and 16 tail-less kites.
No we don't quite have a fifth group of 30, we have 14/15 of one.
So the number of colorless kites in that last group would be (14/15)x3 = 14/5 = 2 and 4/5
We don't have quite three colorless kites in that last group, but we have at least 2.
Similarly the number of tail-less kites in that last group should be (14/15)x4 = 56/15 = 3 and 11/15
We don't have quite 4 tail-less kites in that last group, but we have at least 3.
So altogether, we should have
14 colorless kites and 19 tail-less kites.