Raymond B. answered 21d
Math, microeconomics or criminal justice
mean = sum/N = sum/6
var = sum(xi - mean)^2/N
sd = sqr(var)
10.5 8.5 6.5 3.5 1.5 -.5 have mean 5 = AM
and also have absolute average deviation of 2
var = 30.25 + 12.25 + 2.25 all doubled then divided by 6 = 2(44.75)/6 = 44.75/3
sd = sqr(44.75/3) = about 3.9
try smaller absolute deviations
8, 7, 6, 4, 3, 2 have mean 5 = midpoint = AM
and absolute deviation = 2
var = 9+4+1 double = 28, divided by 3 = 28/3
sd = sqr(28/3) = about 3
still too big
try smaller
7, 7, 6, 4, 3, 3 have mean 5
average deviation = 10/6
var = (1 + 4+ 4)2/6 = 9/3 = 3
sd = sqr3 = about 1.7 that's pretty close