4x^2+40x+3=0

Question

Help me solve it plz nd show work 

Answer 1

HI Kenen, use the Quadratic formula to solve these types of problems.

 

Quadratic formula:

 

x = (-b ± √(b² - 4ac)) / 2a

 

Substituting:

 

a = 4

 

b = 40

 

c = 3

 

x = (-40 ± √(40² - (4 * 4 * 3)) / (2 * 4)

 

x = (-40 ± √(1600 - 48)) / 8

 

x = (-40 ± √1552) / 8

 

x = (-40 ± 39.4 [rounded] ) / 8

 

x = (-40 - 39.4) / 8

 

x = -9.9 [rounded]

 

or 

 

x = (-40 + 39.4) / 8

 

x = -.08 [rounded]

 

Solution:

 

x = -9.9 [rounded] or x = -.08 [rounded].

 

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