Limx→∞[(x+√x)/(3x+2√x+1)]
This limit has the indeterminate form ∞/∞.
Divide the numerator and denominator by x (the highest power of x that appears in the denominator) and simplify:
We get: limx→∞[(1 + 1/√x)/(3 + 2/√x + 1/x)]
As x→∞, 1/√x, 2/√x, and 1/x all approach 0
So the limit above = (1+0)/(3+0+0) = 1/3