Don L. answered 01/13/16
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Griffin, start by finding the slope of the line represented by the information you have. If we use increments of one month on the x-axis, and increments of 65 on the y-axis, we will have two points necessary to find the slope.
The two points are: (7, 780) and (8, 845), since July is the 7th month and August is the 8th month, the x-values are 7 and 8. Use the dollar value for July and August for the y-values.
Slope = change in rise / change in run
Slope = (845 - 780) / (8 - 7)
Slope = 65 / 1
Knowing the slope and one point, we can use the point-slope form of the line to find the equation of the line showing Stephanie's savings.
Point-slope form of the line:
y - y1 = m * (x - x1)
Substitute for y1, m, and x1 using the point: (7, 780) and the slope of 65
y - 780 = 65 * (x - 7)
y - 780 = 65x - 455
Add 780 to both sides:
y = 65x + 325, this is the line that represents Stephanie's savings.
To answer the question, how much did Stephanie start with in her savings account, set x = 0. The answer is $325.
Using the equation, we can find out how much Stephanie's account increased each month. As an example, to find out how much money Stephanie has in December, let x = 12.
y = 65 * 12 + 325
y = 1105, or Stephanie has $1105 in her savings account in December.
Questions?
Don L.
tutor
Hi Griffin, glad to be of help.
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01/13/16
Griffin S.
01/13/16