David W. answered 01/13/16
Tutor
4.7
(90)
Experienced Prof
Given that (x^3-5x^2 +kx-4) has factor (x+2), then there is a value (ax^2 + bx+c) such that:
(x+2)(ax^2+bx+c) = (x^3-5x^2 +kx-4)
(x+2)(ax^2+bx+c) = (x^3-5x^2 +kx-4)
Expanded, this is:
ax^3 + (2a+b)x^2 + (2b+c)x + 2c =
x^3 + (-5)x^2 + (k)x + (-4)
So,
a=1
c= -2
2a+b=-5 or 2(1)+b=-5 so b=-7
2a+b=-5 or 2(1)+b=-5 so b=-7
k = 2b+c or k=2(-7)+(-2) so k=-16
Checking (very important):
(x+2)((1)x^2+(-7)x-2)
x^3 -5x^2 -16x -4 Check!