(8x2-18) / (4x2-10x+6)
= 2(4x2-9) / 2(2x2-5x+3)
- (4x2-9) factors to (2x+3)(2x-3)
- 2x2-5x+3 factors to (2x-3)(x-1) (use the "ac" method)
Substituting in the factors:
= 2(2x+3)(2x-3) / 2(2x-3)(x-1)
Cancelling common terms in the numerator and denominator (2 and (2x-3)):
= (2x+3) / (x-1)
Note that x cannot equal 1 or 3/2 as these make the denominator of the original expression equal to zero, which is undefined.