Arthur D. answered 12/22/15
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
60=(25+c)(2/3)t
60/t=(25+c)(2/3)
60=(25-c)(t)
60/t=(25-c)
(25-c)=(25+c)(2/3)
3(25-c)=2(25+c)
75-3c=50+2c
75-50=3c+2c
25=5c
c=5 mph is the speed of the current
check: 60=(25-5)t ---> 60=20t ---> t=3 hours
60=(25+5)(2) (2/3 of 3 is 2)
60=30*2
60=60