how do i solve this? thanks

2x(4x - 3) = 0

so, either

2x = 0 or 4x - 3 = 0

for 2x = 0, x = 0

for 4x - 3 = 0 ---> 4x = 3 ---> x = 3/4

so,

**x = 0 or x = 3/4**-
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how do i solve this? thanks

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2x(4x - 3) = 0

so, either

2x = 0 or 4x - 3 = 0

for 2x = 0, x = 0

for 4x - 3 = 0 ---> 4x = 3 ---> x = 3/4

so, **x = 0 or x = 3/4**

Hi Mathalina, This is already factored. There are two solutions. 2x=0 or 4x-3=0.

Therefore x=0 or 4x=3.

Solution 1)x=0.

Solution 2)x=3/4.

It's a logic problem:

What values of 'x' will make the expression 2x(4x-3) truly equal to zero.

You can make this true with multiple values as only one of the two factors (2x OR (4x-3)) needs to equal zero for the expression to equal 0. (Anything multiplied by 0 equals 0) So now you simply need to figure out what 2 numbers x could be that would the answer 0. (Hint: Set each factor equal to 0 and solve that way)

Check your work by substituting what you believe to work back into the original equation and solve it out... Does it arrive at 0? If yes for each solution, (again you should have 2, one from each factor) you're done!

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