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Question

could someone help me with this please!!!!

 

Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation 15. Find P3, which is the IQ score separating the bottom 33% from the top 97%

Answer 1

mean IQ = 105, sd = 15

what scores are from 33rd to 97th percentiles??

z scores for 33 and 97 = -.954 to 1.881

-.954 = (IQ - 105)/15

IQ =15(-.954) + 105 = 90.69

1/991= (IQ - 105)/15

IQ = (1.881)(15) + 105 = 133.215