Prove 1 - sin^{2}x / cosx = sin2x / 2sinx I tried do both LHS and RHS. Got stuck after a step or two. 10/28/2013 | Lawson from Markham, VA | 1 Answer | 0 Votes Mark favorite Subscribe Comment Comments Hi Lawson, have you written out your question correctly? Is the equation supposed to be 1 - sin^{2}x/cosx = sin2x/2sinx instead of what you have written? 10/28/2013 | Efe M. Yes, the question was typed incorrectly. Fixed it now, thanks. 10/28/2013 | Lawson from Markham, VA Comment
Hi Lawson, have you written out your question correctly? Is the equation supposed to be 1 - sin^{2}x/cosx = sin2x/2sinx instead of what you have written? 10/28/2013 | Efe M.
(1-sin^{2}x)/cosx=sin2x/2sinx cos^{2}x/cosx=cosx sin2x/2sinx=2sinxcosx/2sinx=cosx 10/28/2013 | Michael F. Best answer Comment
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