zeros:-3,-1,2 degree 3 how i do it

Question

zeros:-3,-1,2 degree 3 how i do it

Answer 1

zeros: -3, -1, 2

(x-[-3]), (x-[-1]), (x-2) to begin with

(x+3), (x+1), (x-2)

multiply the three binomials together

(x+3)(x+1)(x-2)

(x+3)(x^2-x-2)

(x^3-x^2-2x+3x^2-3x-6)

(x^3+2x^2-5x-6) is the polynomial

Answer 2

Since our roots are -3,-1 &2 we can write them as

 

(x+3)(X+1)(X-2)

 

 

Now go ahead  multiply or foil the above and we get

 

 

(x^2+4x+3)(X-2)

 

= x^3+4x^2+3x-2x^2-8x-6

 

= x^3+2x^2-5x-6

 

thats your polynomial good luck.