Hilton T. answered 12/05/15
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Former university lecturer with over 12 years experience
1. compute the initial horizontal and vertical components of the velocity.
Vix = 20 cos 46o = 13.89 m/s = constant
Viy = 20 sin 46o = 14.39 m/s
2. Determine the time of flight (from initial position to the crossbar).
T = Dx/Vx = 36.0m / 13.89 m/s = 2.59 seconds
3. Determine the height of the ball at 2.59 seconds.
a = -g = 9.81 m/s2
Dy = ViyT + 0.5 aT2 = 14.39 x 2.59 + 0.5 x 9.81 x (2.59)2 = 4.37 m
This height is higher than the crossbar by 4.37 - 3.05 = 1.32 m