precalc hw

Question

Let the angles of a triangle be α, β, and γ, with opposite sides of length a, b, and c, respectively. Use the Law of Sines to find the remaining sides. (Round your answers to one decimal place.)
α = 71°; β = 37°; a = 37

Answer 1

b/sin37 =37/sin71

b = 37sin37/sin71 =37(.602) /.946 = 23.54

C=180-108 = 72 degrees

c/sin72 = 37/sin71 = 37.20

a/sinA = b/sinB = c/sinC

37/sin71 = 23.54/sin37 = 37.20/sin72

the triangle has sides 37, 23.5, and 37.2

with angles 71, 37 and 72 degrees