The friction force is 6000 N. How far does it skid?

Hey again, Sierra -- braking decel is 6000N/1200kg = 5 m/s/s taking 6 secs to stop ...

ave speed of 15m/s moving for 6 sec

**travels 90m**... Regards :)-
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The friction force is 6000 N. How far does it skid?

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Hey again, Sierra -- braking decel is 6000N/1200kg = 5 m/s/s taking 6 secs to stop ...

ave speed of 15m/s moving for 6 sec **travels 90m **... Regards :)

Because the car completely stops you can apply the standard formula connecting the acceleration, distance traveled, initial and final speed. Let "a" be the acceleration, v_{i
}= 30m/s (initial speed), v_{f} = 0 -final speed, F -force of friction, "m" - mass. If the distnace traveled is "d", then we have

2ad = v_{f}^{2} - v_{i}^{2} = -900 m^{2}/s^{2}

The force of friction is acting in opposite direction. Thus,

We obtain for d (after canceletaions)

d = 900m/2x5 = 90 m

Numerical answer only please... :)

90 m

(see your previous problem)

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