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A 1200 kg car going 30 m/s skids to a rest.

The friction force is 6000 N. How far does it skid?

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Brad M. | Professional Tutor: STEM plus Business, Accounting, and InvestmentProfessional Tutor: STEM plus Business,...
4.9 4.9 (219 lesson ratings) (219)
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Hey again, Sierra -- braking decel is 6000N/1200kg = 5 m/s/s taking 6 secs to stop ...
ave speed of 15m/s moving for 6 sec travels 90m ... Regards :)
Grigori S. | Certified Physics and Math Teacher G.S.Certified Physics and Math Teacher G.S.
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Because the car completely stops you can apply the standard formula connecting the acceleration, distance traveled, initial and final speed. Let "a" be the acceleration, vi = 30m/s (initial speed), vf = 0 -final speed, F -force of friction,  "m" - mass. If the distnace traveled is "d", then we have
 
                                  2ad = vf2 - vi2 = -900 m2/s2
The force of friction is acting in opposite direction. Thus,
 
                       aF/m = - 6000 N/1200 kg = - 5m/s2
 
We obtain for d (after canceletaions)
 
                             d = 900m/2x5 = 90 m
      
Andre W. | Friendly tutor for ALL math and physics coursesFriendly tutor for ALL math and physics ...
5.0 5.0 (3 lesson ratings) (3)
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Numerical answer only please... :)
90 m
 
(see your previous problem)