Mark M. answered 11/30/15
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
The half-life of Carbon-14 is 5730 years. Since more than half remains the answer should be less than 5730 years.
A = A0(0.5)t/h
0.58A0 = A0(0.5)t/5730 divide both sides by A0
0.58 = 0.5t/5730 take natural log of both sides
ln 0.58 = (t/5730) ln 0.5 calculate ln
-0.54 ≈ (t/5730) (-0.69) multiply both sides by 5730
-3094.2 ≈ -0.69 t divide both sides by -0.69
4484.45 ≈ t
The mummy is approximately four thousand four hundred years old.
Elexa J.
this answer is wrong it is actually 4501.87748298 so around 4501.9 years03/26/21