Y=-2(x+2)^2+2

Question

Y=-2(x+2)^2+2

 

I need the y intercept and vertex. 

thanks

Answer 1

y=a(x-h)²+k is the equation of a parabola where (h,k) is the vertex

y=-2(x+2)²+2

vertex=(-2,2)

let x=0

y=-2(0+2)²+2

y=-2(2)²+2

y=-2(4)+2

y=-8+2

y=-6 for the y-intercept