The sign must remain in equilibrium, that is, NOT in motion by the
forces acting on it. In this problem, only a gravity down force of
150N is acting on it. It is being resisted by two diagonal ropes. The
diagonal force in the rope can be resolved into vertical and horizontal
components. If we were to isolate the sign with the forces acting
on it, commonly referred to as "taking a free-body diagram," we
would have a diagram as illustrated at the following URL...
https://www.wyzant.com/resources/files/405784/equilibrium_forces
Adding vertical forces "(P)v" must equal to zero, adding horizontal
forces "(P)h" must equal to zero.
Recognize that the resultant force in the rope "(P)resultant" is
simply the hypotenuse of a right triangle at an angle of 30deg from
horizontal with vertical and horizontal force components "(P)v and
(P)h" as its legs. This value is easily calculated.