Doug C. answered 11/28/15
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Assuming the two functions are y=2x2 and y = x2 + 4.
It is necessary to find the x-coordintates of the points of intersection so that we know the interval over which to integrate. It is also helpful to sketch the graph.
Substitute 2x2 into the 2nd function for y and solve for x. This gives +/- 2 for x.
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The 2nd function is actually "above" the first one.
So (hard to display limits of integration as -2 to 2--at least so far I have not figured it out), so the following is sort of messy:
∫2 [(x2+4) - 2x2]dx = ∫ (4-x2) = 4x - x3/3 ]-22 = [(8 - 8/3) - (-8 + 8/3)] = 16 - 16/3 = 48/3 - 16/3 = 32/3.
-2