
David W. answered 11/27/15
Tutor
4.7
(90)
Experienced Prof
From Wikipedia:
"A univariate quadratic function can be expressed in three formats:
f(x) = ax2 + bx +c is called the standard form,
f(x) = (x-x1)(x-x2) is called the factored form, where x1 and x2 are the roots of the quadratic function and the solutions of the corresponding quadratic equation.
f(x) = a(x-h)2 + k is called the vertex form, where h and k are the x and y coordinates of the vertex, respectively."
"A univariate quadratic function can be expressed in three formats:
f(x) = ax2 + bx +c is called the standard form,
f(x) = (x-x1)(x-x2) is called the factored form, where x1 and x2 are the roots of the quadratic function and the solutions of the corresponding quadratic equation.
f(x) = a(x-h)2 + k is called the vertex form, where h and k are the x and y coordinates of the vertex, respectively."
The problem gives us: h=2, k=2 and point (3,-3) is on the curve:
Let's find the value of (a) using the point (3,-3):
f(x) = a(x-h)2 + k
-3 = a(3-2)2 + (2)
-3 = a(1) + 2
-5 = a
The equation is f(x)= (-5)(x-2)2 + 2