
Steven C. answered 11/25/15
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Mathematics Tutor Steven
The key to this problem is to identify when quadratic is equivalent to zero and we know that if y = x2 - x - 12, then when y ≥ 0, we have the inequality hold true.
y = 0
x2 - x - 12 = 0
(x-4)(x+3) = 0
when x = 4, -3 we have that y = 0.
whenever x > 4 or x < -3. We will have y > 0. thus the solution set is:
x ∈ (-∞,-3] , [4, ∞) (x is contained in the two ranges).