Y=4/3x - 4/6 in standard form

Question

I must write an equation that passes through (1/2,6) with a slope of 4/3. Then express the equation in standard form

Answer 1

The standard form of an equation is simply an equation in the form of Ax + By = C.

 

To begin, you have 2 points and a slope. Put this into the point slope form as specified below:

 

y - y1 = m (x - x1), this will give you y - 6 = 4/3 (x - 1/2)

 

Next multiply this out as displayed below:

 

y - 6 = 4/3(x) - 4/6, which you already have.

 

Finally, convert it to standard form:

 

4/3(x) - y = - 5 1/3.

 

This is essentially the same as multiplying both sides by 3 as well, which would be

 

4x - 3y = - 16

 

You can verify that this is correct by simply plugging in your point to ensure that  4(1/2) - 3(6) = -15, and it does, because 2 - 18 = -16