my problem is:

y (less than or equal to) (-2/3)X + 3

y (less than or equal to) (4/3)X - 3

I know how to graph it I just do not understand the shading and how to know which way to shade it, if you could help me it'd be appreciated!

Tutors, sign in to answer this question.

Simply put, test a couple of numbers.

Once you've drawn the line on your graph (in simple problems) you will have two areas. Use an x value that fits inside one of the shaded areas and calculate the corresponding y value.

If that x value satisfies the inequality shade in that area of the in equality

Tiffany D. | Math and ScienceMath and Science

When you are looking at a problem like this, think of the y-axis as your dividing line. Because both of these equations are linear, you will have to shade either above or below.

Start with the first equation and look at any number for x and plug it into your equation. You will solve for y (This will give you an x and y coordinate. This can be done several times, and each time, the resulting x and y numbers should be in the area you want to shade (ie: below the line because y in this case is less than) Because there is an equal sign underneath, the line will be solid.

For the second equation, it also shows less than or equal to (again plug in numbers as above for x and solve for y to get your points) Again this line is solid (hence the equal sign)

To understand where the main area of shading is, gets a bit tricky, but if you did it right, you will have and area where the shaded regions of the individual graphs meet. This is where your final shading should be!

Hope this helps!

Graph the two lines.

Pick four points in each of the four quadrants around the intersection.

Point of intersection is -2/3x + 3 = 4/3x-3 => 3 + 3 = 4/3x+ 2/3x => 6 = 6/3x

x = 3

Use either equations and plug in x = 3 to find y.

y = 4/3(3) - 3 = 1

Pick x=0,y=0 plug them into each equations and see which is true.

1 <= -2/3(3)+3 => 1 <= -2+3

1 <= 1 true.

Point 0,0 is less that or equal to that equation. This side of equation one is shaded (not all of it. check the second equation).

How about the other equation.

1 <= 4/3(3) + 3

1 <= 4 + 3 True.

Point 0,0 is less that or equal to the second equation. shade that side of the second equation and the first.

The other side of each equations are not shaded (the other three quadrants)

Already have an account? Log in

By signing up, I agree to Wyzant’s terms of use and privacy policy.

Or

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Your Facebook email address is associated with a Wyzant tutor account. Please use a different email address to create a new student account.

Good news! It looks like you already have an account registered with the email address **you provided**.

It looks like this is your first time here. Welcome!

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Please try again, our system had a problem processing your request.

Jennifer W.

Patient, Thorough, and Knowledgeable Chemistry, French, and Math Tutor

$7.50 per 15 min

View Profile >

Trevor G.

Mathe-Magician: Excellent with Algebra, Arithmetic

$8.75 per 15 min

View Profile >

Elizabeth H.

Effective and Fun Language and Math Tutor

$10 per 15 min

View Profile >