Graph the two lines.
Pick four points in each of the four quadrants around the intersection.
Point of intersection is -2/3x + 3 = 4/3x-3 => 3 + 3 = 4/3x+ 2/3x => 6 = 6/3x
x = 3
Use either equations and plug in x = 3 to find y.
y = 4/3(3) - 3 = 1
Pick x=0,y=0 plug them into each equations and see which is true.
1 <= -2/3(3)+3 => 1 <= -2+3
1 <= 1 true.
Point 0,0 is less that or equal to that equation. This side of equation one is shaded (not all of it. check the second equation).
How about the other equation.
1 <= 4/3(3) + 3
1 <= 4 + 3 True.
Point 0,0 is less that or equal to the second equation. shade that side of the second equation and the first.
The other side of each equations are not shaded (the other three quadrants)