((8v+8)(2v+1))/(24(v+1))...factor numerator, denominator
To find the excluded value, set the denominator equal to zero.
24(v+1)=0
v+1=0......divide both sides by 24
∴ v= -1.....subtract 1 from both sides
So v= -1 is excluded from the solution set because the
denominator in the original expression would be zero, and
division by zero is undefined.