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How much work is done by a 45 N force acting 35 degrees above the horizontal in pulling a block 9 m across a horizontal surface?

Numerical answer only please

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Jim S. | Physics (and math) are fun, reallyPhysics (and math) are fun, really
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W=F d cos(theta)=45 x 9 cos(35) = 331.76 J
 
Jim
Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
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Hi Sierra;
Force=45N, 35-degrees above horizontal
Distance=9m
 
Work=(force)(distance)
 
The issue created by the degrees above horizontal is that a triangle is created.  We need to understand the horizontal force of this triangle.
The hypotenuse is = 250N
We need the value of the adjacent...
adjacent/hypotenuse
Therefore, we need the value of the cos of 35-degrees.
 
 
45N (cos 35-degrees)=45N(0.82)=36.9N
Work=(36.9N)(9m)=332 joules
Andre W. | Friendly tutor for ALL math and physics coursesFriendly tutor for ALL math and physics ...
5.0 5.0 (3 lesson ratings) (3)
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330 joules.