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How much work is done by a 45 N force acting 35 degrees above the horizontal in pulling a block 9 m across a horizontal surface?

Numerical answer only please
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3 Answers

W=F d cos(theta)=45 x 9 cos(35) = 331.76 J
Hi Sierra;
Force=45N, 35-degrees above horizontal
The issue created by the degrees above horizontal is that a triangle is created.  We need to understand the horizontal force of this triangle.
The hypotenuse is = 250N
We need the value of the adjacent...
Therefore, we need the value of the cos of 35-degrees.
45N (cos 35-degrees)=45N(0.82)=36.9N
Work=(36.9N)(9m)=332 joules
330 joules.