Numerical answer only please

W=F d cos(theta)=45 x 9 cos(35) = 331.76 J

Jim

Numerical answer only please

Tutors, please sign in to answer this question.

Fairport, NY

W=F d cos(theta)=45 x 9 cos(35) = 331.76 J

Jim

Middletown, CT

Hi Sierra;

Force=45N, 35-degrees above horizontal

Distance=9m

Work=(force)(distance)

The issue created by the degrees above horizontal is that a triangle is created. We need to understand the horizontal force of this triangle.

The hypotenuse is = 250N

We need the value of the adjacent...

adjacent/hypotenuse

Therefore, we need the value of the cos of 35-degrees.

45N (cos 35-degrees)=45N(0.82)=36.9N

Work=(36.9N)(9m)=332 joules

New Wilmington, PA

330 joules.

David M.

Experienced Teacher and Tutor for Math, Science and beyond!

New York, NY

4.9
(668 ratings)

Jeffrey G.

Former Med-Student turned Professional Science Tutor

Brooklyn, NY

5.0
(344 ratings)

John E.

Physics and Math tutor - Masters from Cornell and Columbia University

New York, NY

4.8
(124 ratings)

Find a tutor fast. Get the app.

Are you a tutor? Get the app for tutors

© 2005 - 2016 WyzAnt, Inc. - All Rights Reserved