Numerical answer only please

W=F d cos(theta)=45 x 9 cos(35) = 331.76 J

Jim

Numerical answer only please

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Fairport, NY

W=F d cos(theta)=45 x 9 cos(35) = 331.76 J

Jim

Middletown, CT

Hi Sierra;

Force=45N, 35-degrees above horizontal

Distance=9m

Work=(force)(distance)

The issue created by the degrees above horizontal is that a triangle is created. We need to understand the horizontal force of this triangle.

The hypotenuse is = 250N

We need the value of the adjacent...

adjacent/hypotenuse

Therefore, we need the value of the cos of 35-degrees.

45N (cos 35-degrees)=45N(0.82)=36.9N

Work=(36.9N)(9m)=332 joules

New Wilmington, PA

330 joules.

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