One number is 4 more than another. The difference between their squares is 96.

Question

One last question 

Answer 1

x = y+4

x²-y²=96

 

(y+4)²-y²=96

y²+8y+16-y²=96

8y+16=96

8y=80

y=10

 

x=y+4 =14

 

 

Your numbers are 10 and 14.

Answer 2

Square root of 96 is about 10, so let's assume the first number is 10. Add 96 to 10² , it is 196. 196-100 = 96, this satisfies the condition for having difference between squares as 96. Now, square root of 196 is 14, 14-10 = 4 this satisfies the condition for one number is 4 more than another.

 

So the two numbers are 10 and 14.