Sarah M.

asked • 11/10/15

Find the probability of picking a red or yellow marble from a bag containing 6 red, 2 green, and 3 yellow marbles.

Find the probability of picking a red or yellow marble from a bag containing 6 red, 2 green, and 3 yellow marbles.
 
I believe this is an Exclusive event
 
P(A) = red marbles = 6/11
P(B) = yellow marbles = 3/11
P(A and B) = P(A + B) = 6/11 + 3/11
P(A and B) = 9/11
 
This seems too easy. Am I correct?

Arthur D.

tutor
9/11 is correct but you are using the word AND in your answer and you should be using the word OR in your answer because you said OR in your problem; OR means to add the probabilities like you did
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11/10/15

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Katherine A. answered • 11/10/15

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P(A) = red marbles = 6/11 correct
P(B) = yellow marbles = 3/11 correct
P(A and B) = P(A + B) = 6/11 + 3/11--> for this one you need to multiply the probability of each event 36/121
P(A and B) = 9/11.(incorrect)...a good rule of thumb to think about is if you are adding events the probability will go down...you should get a smaller number 
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