
Mark M. answered 11/09/15
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Mathematics Teacher - NCLB Highly Qualified
A = A0(0.5)t/h, where A0 = starting amount, t = time, h = half-life
0.6A0 = A0(0.5)t/5730 divide both sides by A0
0.6 = (0.5)t/5730 take natural log of both sides
ln 0.6 = ln (0.5)t/5730 using law of logs
ln 0.6 = (t/5730) ln (0.5) calculate ln
-0.51825624 ≈ (t/5730)(-0.693147181) multiply both sides by 5730
-2969.0826 ≈ -0.693147181t divide both sides the right coefficient
4284.2391 ≈ t
The age of the sample is approximately 4284 years.
Mark M.
11/09/15