Christopher G. answered • 11/09/15
Tutor
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Math, Science, Test Prep
Since the block is stationary, the friction force must be just large enough to cancel out the component of the weight force in the direction parallel to the ramp.
Ff = mg sin θ = (5.0 kg)(9.8 m/s2)(3/5) ≈ 30 N
Ff = mg sin θ = (5.0 kg)(9.8 m/s2)(3/5) ≈ 30 N
