Michael J. answered 11/08/15
Tutor
5
(5)
Effective High School STEM Tutor & CUNY Math Peer Leader
Let x = the cost of a shirt
Let y = the cost of a slack
Let z = the cost of a coat
Using these variables, we can set up equations that represents the total cost for each set.
3x + y = 12.96 eq1
5x + 3y + z = 36.91 eq2
5x + z = 20.44 eq3
We have here a system of equations. Three equations with three variables. Each equation has the same value of x, y, and z. To solve system of equations, we use substitution and elimination methods to reduce the number of equations and variables. This makes is easier to solve for the variables.
We can use the substitution method, to get two equations with two variables. Substitute eq1 into equation eq2. From eq1,
y = 12.96 - 3x
5x + 3(12.96 - 3x) + z = 36.91
5x + 38.88 - 9x + z = 36.91
-4x + z = -1.97 new eq2
5x + z = = 20.44 eq3
Next, we can subtract eq3 from new eq2 to eliminate the z terms.
-9x = -22.41
Divide both sides of the equation by -9.
x = 2.49
Substitute this value of x into new eq2 to solve for z and eq1 to solve for y.
-4(2.49) + z = -1.97
-9.96 + z = -1.97
z = 7.99
y = 12.96 - 3(2.49)
y = 12.96 - 7.47
y = 5.49
Each shirt costs $2.49
Each slack costs $5.49
Each coat costs $7.99