Hassan F. answered 11/07/15
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The addition of S2- ion to Cr(OH)3(s) does not result in the formation of Cr2S3(s) because Cr2S3(s) is water soluble, it has to do with the d-orbital of Cr that can gain an electron to become half filled, it has a higher solubility constant. Also, Cr(OH)3(s) has a higher rate of formation, it is less soluble, making it the more likely product to form.
The addition of S2- ion in to Fe(OH)2(s) results in the formation of FeS(s) because Fe has a d-orbital that is more than half filled, losing the effect of a half-filled d-orbital, making it insoluble in water; its rate of formation is high and rate of solubility is low.