Find the tension answer in newtons

Question

A block of mass 1.88439 kg lies on a friction- less table, pulled by another mass 4.98587 kg under the influence of Earth’s gravity. The acceleration of gravity is 9.8 m/s2 .What is the magnitude of the tension T of the rope between the two masses? Answer in units of N.

Answer 1

Let m = 1.88439 kg be the mass of the block

M=4.98587 kg the mass of the second. 

m lies on a smooth surface.  The only force acting on m is the tension in the rope =T

Drawing the free body diagram of the mass with M:  In the x direction the net force is zero.

In the y direction there are two forces:

T pointing upwards and the weight of M pointing downwards.

The mass M is in equilibrium.  Therefore T = M g

T = (4.98587 kg)(9.8 m/s^-2)= 48.86 Newtons