Quadratic Equations:

Question

Quadratic Equations: Solve for the values of x using Two(2) methods ( Factoring and Formula) 1.) x2 – 36 = 0 2.) x2 – 8x + 15 = 0 3.) x 2 – 2x - 24 = 0 4.) 2x2 + 3x - 2 = 0 5.) 3x2 + 8x – 3 = 0

Answer 1

1. Factoring:   =(x+6)(x-6)......x=6, -6

    Formula:   a=1, b=0, c=-36

2. Factoring:   =(x-3)(x-5).......x=3, 5

    Formula:   a=1, b=-8, c=15

3. Factoring:   =(x-6)(x+4)......x=-4, 6

    Formula:   a=1, b=-2, c=-24

4. Factoring:   =(2x-1)(x+2)....x=-2, 1/2

    Formula:   a=2, b=3,c=-2

5. Factoring:   =(3x-1)(x+3)....x=-3, 1/3

    Formula:   a=3, b=8, c=-3

 

For each of the "Factoring" terms inside parentheses, equate each

      term to zero, solve for "x"

For each of the "Formula" values "a, b, c" substitute into the eqn......

 

       -b±√(b²-4ac)

x =  ----------------  which yields 2 solutions for "x"

              2a

 

Results should be identical to the "Factoring" values listed for "x"