Jennifer W. answered 11/03/15
Tutor
5
(7)
General Tutor - Certified in Multiple Subjects
First, you must find a common denominator. I would use 5x2 for this, since the second fraction already has that denominator, and everything can be easily changed to 5x2.
So, in the first portion, on the left side of the equation, we have to get the bottom to be 5x2.
5(x-3) = x-5 + x(1)
5(x2) 5x2 x(5x)
I apologize for my poor formatting. Please bare with me. So, in order to get the first fraction tobe 5x2 on the bottom, we need to multiply the fraction by 5/5. For the third fraction to change, we have to multiply it by x/x. This way, we are still multiplying by one, so we are not actually changing the equation; we are only changing how it looks. Similar to the way that 2/4 still equals 1/2, even though it looks different. This leads the equation to be:
5x-15 = x-5 + x
5x2 5x2 5x2
Now, we just solve for x.
5x-15=5x2(x-5+x)
5x2
5x-15=x-5+x
5x-15=2x-5
3x=10
x=10/3.
Jennifer W.
Yes, I do. All math up through Calculus. :)
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11/04/15
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11/04/15