
Dominic S. answered 11/02/15
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Math and Physics Tutor
This is the same quadratic relationship as in the problem you previously posted, H(D) = .25D2 + 1
Here, you're told the depth (H=4), and asked to find the distance D. So, plug it in.
4 = .25D2 + 1
3 = .25D2
12 = D2
D = √12 = 3.46