Physics Help?

Question

A 200 N box is pushed up an incline 10 m long and 3 m high. The average force (parallel to the plane) is 120 N.

a.) How much work is done?

b.) What is the change in the PE of the box?

c.) What is the change in KE of the box?

d.) What is the frictional force on the box?

Answer 1

A 200 N box is pushed up an incline 10 m long and 3 m high. The average force (parallel to the plane) is 120 N.

 

a) W=F*d

W= 120 N*10 m

   =1200 J

b) ΔPE = mgΔh

   ΔPE = 200N * 3m

           = 600 J

c) W=ΔPE +ΔKE 

    1200 J = 600 J +ΔKE 

ΔKE=600J

d)  if object not moving ainsufficient information.  if the box is moving at a constant velocity then ΔKE = 0 and F_f=120-200sin(17.46)=60

A 21200 N box is pushed up an incline 10 m long and 3 m high. The average force (parallel to the plane) is 120 N.