
Darren L. answered 10/28/15
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To be a function, it has to pass the "vertical line test" which means for each x-value there is at most one y-value.
So,
let's rewrite it as y2 = x2.
Now if we want it to be a function of y we have to reduce it to just the first power of y. Here we can do that by taking the square root. So, you get
sqrt(y2) = sqrt(x2).
Now if you want to take square roots of anything that is a square (which means it's of the form z2) you must consider both the positive and negative values, since z2 = (-z)2 , and in this case y2 = (-y)2.
so then when we reduce the equality sqrt(y2) = sqrt(x2) we get
y = +/-sqrt(x2). When we reduce sqrt(x2) it's a bit redundant to put +/- y = +/- x. So we leave it as
y = +/- x.
Now that it's an equality with just y isolated, we test whether it's a function.
so let's take x = something arbitrary, let's say 1.
then y = 1 and y = -1. Clearly that does not pass the function test (or vertical line test as I mentioned earlier).

Darren L.
I realize a part of my explanation can be explored more. Unnecessary to the answer but to help you understand it a bit more.
Take the part where we are doing y = +/-sqrt(x2)
We can also observe that x2 is always positive and sqrt as a function only takes nonnegative values. so you could also rewrite it as y = +/-|x| using the absolute value function. |x| is always nonnegative which corresponds to the previous statement.
We can also observe that x2 is always positive and sqrt as a function only takes nonnegative values. so you could also rewrite it as y = +/-|x| using the absolute value function. |x| is always nonnegative which corresponds to the previous statement.
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Darren L.
and you're welcome!
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Antonio P.
10/28/15