Mark M. answered 10/21/15
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = 2x2 - 2x + 6 0 ≤ x ≤ 6
Since f(x) is continuous on [0,6], the absolute extrema occur either at a critical point or an endpoint.
To find the critical points, solve the equation f'(x) = 0
4x - 2 = 0
x = 1/2
1/2 is the only critical point on the interval
Check f(1/2), f(0), and f(6):
f(1/2) = 5.5
f(0) = 6
f(6) = 66
Absolute max = f(6) = 66
Absolute min = f(1/2) = 5.5
Kimberly K.
10/21/15