Mark M. answered 10/20/15
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Retired math prof. Very extensive Precalculus tutoring experience.
If x < 0, then lxl = -x
So, limx→0- [(lxl - x)/x] = limx→0- [-2x/x] = -2
If x > 0, then lxl = x
So, limx→0+ [(lxl - x)/x] = limx→0+ [0] = 0