Mark M. answered 10/19/15
Tutor
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(955)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let A(t) = amount remaining in t years
A(t) = A0ekt, where A0 is the initial amount and k is a constant to be determined
We know that A(5730) = 0.5A0, so A0e5730k = 0.5A0
e5730k = 0.5
5730k = ln(0.5)
k = -0.000121
A(t) = A0e-0.000121t
So, if A(t) = 0.74A0, then 0.74A0 = A0e-0.000121t
0.74 = e-0.000121t
ln(0.74) = -0.000121t
t = 2488.4718
The parchment is about 2488 years old.
Mark M.
tutor
0.5 = 1/2 A(5730) = half of original amount
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05/10/22
Johanna A.
Where did 0.5 come from.05/10/22