Dom V. answered 10/19/15
Tutor
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Cornell Engineering grad specializing in advanced math subjects
Gravitational force is given by
F= GMm/r2.
G is the gravitational constant, M and m are the masses of the two bodies exerting gravitational force on each other, and r is the distance between their centers of mass. On Earth, M becomes the mass of earth and r becomes the radius of earth. We normally lump GM/r2 together as g=9.8 m/s2 (i.e. weight is just gravitational force at Earth's surface):
Fweight=G Mearthmperson/r2earth = (GMearth/r2earth)mperson = gm.
This question is asking what happens to F as you scale the constituent parts of g.
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1. Your mass is constant, always. No change here.
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2. On planet X, there would be a new acceleration due to gravity (call it gX), given by
gx=GMX/rx2
We know Mx=Mearth and rx=rearth/2 (so rx2=r2earth/22 = r2earth/4). Plugging these in:
gx=[GMearth]/[r2earth/4] = [4GM]/[r2] = 4*g.
So, Fx=mgx=(m)(4gearth) =4(mgearth)=4 Fearth
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3. The same idea follows, except the ladder causes the r on planet X to increase back to rearth. Your weight would be the same at this height since the mass of X is the same as Earth's.