Hi Luke,
This is a fun problem that requires some thinking. . .
They began at 8:30, rested for 1 1/2 hours and got back at 4:00. That means that their rowing time was 6 hours.
They traveled a total of 24 miles . . . that means that they rowed 12 miles upstream and then 12 miles downstream.
Let X = their rowing speed in still water
Then they traveled at a rate of X -3 miles per hour upstream because the current slowed them down by 3 mph
They traveled at a rate of X + 3 miles per hour downstream because the current gave them a push by 3 mph
The formula is distance/rate = time. The time up is 12/(X-3) and the time back is 12/(X+3) and the total time is 6 hours:
12/(X - 3) + 12/ (X + 3) = 6
multiply first fraction by (X+3)/(X+3) and the second fraction by (X-3)/(X-3) to get a common denominator:
(12(X+3) + 12 (X-3))/ (X+3)(X-3) = 6
(12X + 36 +12X - 36)/ (X^2 -9) = 6
24X / (X^2 -9) = 6
Cross multiply--> 24X = 6X^2 - 54
Move everything to the right side of the equation-->0 = 6X^2 - 24X - 54
Divide everything by 6 --> x^2 - 4X - 9 = 0
Use the quadratic equation with a = 1 b = -4 c = -9
X = (4 +/- sq rt (16 + 36) / 2
X = (4 +/- sq rt 52) / 2
X = (4 +/- 7.2) / 2
X = 5.6 miles per hour (we can disregard the negative value of X)
This means that they traveled 2.6 mph upstream (by subtracting 3 mph from 5.6 mph)
The distance is 12 miles
Now you can calculate the time to Elk Island with the formula distance/rate = time and then figure what time they arrived at Elk Island since they began at 8:30 AM
Have fun.
Dan
Luke W.
10/15/15