the function h(t)=256t-16t^2 models the approximate height of an object t seconds after it is launched. How many seconds does it take the it to hit the ground?

Question

I need an answer quickly. It is urgent.

Answer 1

So if this expression models the height of an object, when the object hits the ground it is safe to assume that h=0 if we use the ground as our reference.

 

Thus, 0=256t-16t^2.

 

This is now a factoring problem.

 

I can factor out a -16 because both numbers are divisible by it:

-16(t²-16t)=0

 

From there we can get the expression t²-16t=0

 

And this factors to t(t-16)=0 which gives you t=0 and t=16.

 

0 seconds would be when/right before the object is launch (makes sense right?) and 16 seconds would be when it lands.

 

Hope this helps!!